Battle of Cerro del Borrego

Battle of Cerro del Borrego Part of the French intervention in Mexico Date 13 June 1862 Location Orizaba, Veracruz, Mexico Result Mexican Empire-French victory Belligerents Mexican Republicans Mexican Empire French Empire Commanders and leaders Jesús Ortega Unknown

French intervention in Mexico (1861–1867) Fortín Las Cumbres Atlixco Puebla Barranca Seca Cerro del Borrego Jonuta Siege of Puebla San Pablo del Monte Tampico 2nd Atlixco Camarón Mexico City Chiapa de Corzo Morelia Guanajuato Guadalajara Jahuactal San Juan Bautista Mazatlán Acapulco Nanahuatipam Majoma Monterrey Matamoros Totoapan Colima Jiquilpan San Pedro Cuauhtémoc El Rosario Tacámbaro Soyaltepec La Loma Parral Chihuahua Álamos Ixmiquilpan Bagdad Santa Isabel Chihuahua Siege of Jonuta Santa Gertrudis Miahuatlán Juchitán La Carbonera Guayabo Guadalajara Villa de Álvarez San Jacinto Monterrey 3rd Puebla Lomas de San Lorenzo Siege of Querétaro Mexico City

The Battle of Cerro del Borrego took place on 13 June 1862 in the vicinity of the current municipality of Orizaba in the state of Veracruz, Mexico. It was fought between the Mexican republican army under General Jesús Gonzalez Ortega and troops of the Second Mexican Empire during the French intervention in Mexico.^[1]

Before General González Ortega's troops incorporation to General Zaragoza's troops in San Andrés Chalchicomula, he received orders to pass through Perote in order to reach the northern part of Orizaba heading to La Perla and then occupy Cerro del Borrego, near to Orizaba. During the night of June 14, 1862, the Zacatecas division was discovered and moved away from its position by French troops forcing it to retreat.

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Coordinates: 18°51′58″N 97°07′58″W / 18.8661°N 97.1328°W / 18.8661; -97.1328