Mikhaylov Island

Mikhaylov Island

Mikhaylov Island Location in Antarctica
Geography
Location	Antarctica
Coordinates	66°48′S 85°30′E / 66.800°S 85.500°E / -66.800; 85.500Coordinates: 66°48′S 85°30′E / 66.800°S 85.500°E / -66.800; 85.500
Highest elevation	240 m (790 ft)
Administration
None
Demographics
Population	Uninhabited
Additional information
Administered under the Antarctic Treaty System

Mikhaylov Island is an ice-covered island in the West Ice Shelf of Antarctica, rising to 240 metres (800 ft), 11 kilometres (6 nmi) southeast of Leskov Island. It was discovered by the Soviet expedition of 1956, who named it for Pavel N. Mikhaylov, artist on the Bellingshausen expedition of 1819–21.^[1]

References

 This article incorporates public domain material from the United States Geological Survey document "Mikhaylov Island" (content from the Geographic Names Information System).