United States presidential election in New York, 1836

United States presidential election in New York, 1836

November 3 - December 7, 1836

Nominee Martin Van Buren William Henry Harrison Party Democratic Whig Home state New York Ohio Running mate Richard Mentor Johnson Francis Granger Electoral vote 42 0 Popular vote 166,795 138,548 Percentage 54.63 45.47

President before election Andrew Jackson Democratic Elected President Martin Van Buren Democratic

Elections in New York State
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The 1836 United States presidential election in New York took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose forty-two representatives, or electors to the Electoral College, who voted for President and Vice President.

New York voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won New York by a margin of 9.26%.

Results

References

State Results of the 1836 U.S. presidential election
Candidates	Martin Van Buren William Henry Harrison Hugh White Daniel Webster Willie Person Mangum
General articles	Election timeline
Local results	Alabama Arkansas Connecticut Delaware Georgia Illinois Indiana Kentucky Louisiana Maine Maryland Massachusetts Michigan Mississippi Missouri New Hampshire New Jersey New York North Carolina Ohio Pennsylvania Rhode Island South Carolina Tennessee Vermont Virginia
Other 1836 elections	House Senate Gubernatorial